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Updated: 13 Jun 2026, 12:22:16
E=mc^2
First Equation of Motion
Given:
- Initial velocity =
u - Final velocity =
v - Acceleration =
a - Time =
t
Formula:
v = u + at
Second Equation of Motion
Distance travelled in time t:
s = ut + (1/2)at^2
Third Equation of Motion
Formula:
v^2 = u^2 + 2as
Derivation of the Third Equation
From the first equation:
v = u + at
Therefore,
t = (v - u)/a
Substitute into the second equation:
s = u[(v - u)/a] + (1/2)a[(v - u)/a]^2
Simplifying:
s = (uv - u^2)/a + (v - u)^2/(2a)
Multiplying both sides by 2a:
2as = 2uv - 2u^2 + (v - u)^2
Expanding:
2as = 2uv - 2u^2 + v^2 - 2uv + u^2
2as = v^2 - u^2
Therefore,
v^2 = u^2 + 2as
All Three Equations Together
v = u + at
s = ut + (1/2)at^2
v^2 = u^2 + 2as
These are commonly called Newton's equations (or equations of uniformly accelerated motion). The powers are written in the form you requested, such as v^2, u^2, and t^2.
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Swarnim Raj
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